Integrand size = 12, antiderivative size = 143 \[ \int (a+b \arctan (c+d x))^3 \, dx=\frac {i (a+b \arctan (c+d x))^3}{d}+\frac {(c+d x) (a+b \arctan (c+d x))^3}{d}+\frac {3 b (a+b \arctan (c+d x))^2 \log \left (\frac {2}{1+i (c+d x)}\right )}{d}+\frac {3 i b^2 (a+b \arctan (c+d x)) \operatorname {PolyLog}\left (2,1-\frac {2}{1+i (c+d x)}\right )}{d}+\frac {3 b^3 \operatorname {PolyLog}\left (3,1-\frac {2}{1+i (c+d x)}\right )}{2 d} \]
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Time = 0.15 (sec) , antiderivative size = 143, normalized size of antiderivative = 1.00, number of steps used = 6, number of rules used = 7, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.583, Rules used = {5147, 4930, 5040, 4964, 5004, 5114, 6745} \[ \int (a+b \arctan (c+d x))^3 \, dx=\frac {3 i b^2 \operatorname {PolyLog}\left (2,1-\frac {2}{i (c+d x)+1}\right ) (a+b \arctan (c+d x))}{d}+\frac {(c+d x) (a+b \arctan (c+d x))^3}{d}+\frac {i (a+b \arctan (c+d x))^3}{d}+\frac {3 b \log \left (\frac {2}{1+i (c+d x)}\right ) (a+b \arctan (c+d x))^2}{d}+\frac {3 b^3 \operatorname {PolyLog}\left (3,1-\frac {2}{i (c+d x)+1}\right )}{2 d} \]
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Rule 4930
Rule 4964
Rule 5004
Rule 5040
Rule 5114
Rule 5147
Rule 6745
Rubi steps \begin{align*} \text {integral}& = \frac {\text {Subst}\left (\int (a+b \arctan (x))^3 \, dx,x,c+d x\right )}{d} \\ & = \frac {(c+d x) (a+b \arctan (c+d x))^3}{d}-\frac {(3 b) \text {Subst}\left (\int \frac {x (a+b \arctan (x))^2}{1+x^2} \, dx,x,c+d x\right )}{d} \\ & = \frac {i (a+b \arctan (c+d x))^3}{d}+\frac {(c+d x) (a+b \arctan (c+d x))^3}{d}+\frac {(3 b) \text {Subst}\left (\int \frac {(a+b \arctan (x))^2}{i-x} \, dx,x,c+d x\right )}{d} \\ & = \frac {i (a+b \arctan (c+d x))^3}{d}+\frac {(c+d x) (a+b \arctan (c+d x))^3}{d}+\frac {3 b (a+b \arctan (c+d x))^2 \log \left (\frac {2}{1+i (c+d x)}\right )}{d}-\frac {\left (6 b^2\right ) \text {Subst}\left (\int \frac {(a+b \arctan (x)) \log \left (\frac {2}{1+i x}\right )}{1+x^2} \, dx,x,c+d x\right )}{d} \\ & = \frac {i (a+b \arctan (c+d x))^3}{d}+\frac {(c+d x) (a+b \arctan (c+d x))^3}{d}+\frac {3 b (a+b \arctan (c+d x))^2 \log \left (\frac {2}{1+i (c+d x)}\right )}{d}+\frac {3 i b^2 (a+b \arctan (c+d x)) \operatorname {PolyLog}\left (2,1-\frac {2}{1+i (c+d x)}\right )}{d}-\frac {\left (3 i b^3\right ) \text {Subst}\left (\int \frac {\operatorname {PolyLog}\left (2,1-\frac {2}{1+i x}\right )}{1+x^2} \, dx,x,c+d x\right )}{d} \\ & = \frac {i (a+b \arctan (c+d x))^3}{d}+\frac {(c+d x) (a+b \arctan (c+d x))^3}{d}+\frac {3 b (a+b \arctan (c+d x))^2 \log \left (\frac {2}{1+i (c+d x)}\right )}{d}+\frac {3 i b^2 (a+b \arctan (c+d x)) \operatorname {PolyLog}\left (2,1-\frac {2}{1+i (c+d x)}\right )}{d}+\frac {3 b^3 \operatorname {PolyLog}\left (3,1-\frac {2}{1+i (c+d x)}\right )}{2 d} \\ \end{align*}
Time = 0.12 (sec) , antiderivative size = 212, normalized size of antiderivative = 1.48 \[ \int (a+b \arctan (c+d x))^3 \, dx=\frac {2 a^3 (c+d x)+6 a^2 b (c+d x) \arctan (c+d x)-3 a^2 b \log \left (1+(c+d x)^2\right )+6 a b^2 \left (\arctan (c+d x) \left ((-i+c+d x) \arctan (c+d x)+2 \log \left (1+e^{2 i \arctan (c+d x)}\right )\right )-i \operatorname {PolyLog}\left (2,-e^{2 i \arctan (c+d x)}\right )\right )+2 b^3 \left (\arctan (c+d x)^2 \left ((-i+c+d x) \arctan (c+d x)+3 \log \left (1+e^{2 i \arctan (c+d x)}\right )\right )-3 i \arctan (c+d x) \operatorname {PolyLog}\left (2,-e^{2 i \arctan (c+d x)}\right )+\frac {3}{2} \operatorname {PolyLog}\left (3,-e^{2 i \arctan (c+d x)}\right )\right )}{2 d} \]
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Both result and optimal contain complex but leaf count of result is larger than twice the leaf count of optimal. 278 vs. \(2 (136 ) = 272\).
Time = 0.78 (sec) , antiderivative size = 279, normalized size of antiderivative = 1.95
method | result | size |
derivativedivides | \(\frac {\left (d x +c \right ) a^{3}+b^{3} \left (\arctan \left (d x +c \right )^{3} \left (d x +c +i\right )-2 i \arctan \left (d x +c \right )^{3}+3 \arctan \left (d x +c \right )^{2} \ln \left (1+\frac {\left (1+i \left (d x +c \right )\right )^{2}}{1+\left (d x +c \right )^{2}}\right )-3 i \arctan \left (d x +c \right ) \operatorname {polylog}\left (2, -\frac {\left (1+i \left (d x +c \right )\right )^{2}}{1+\left (d x +c \right )^{2}}\right )+\frac {3 \operatorname {polylog}\left (3, -\frac {\left (1+i \left (d x +c \right )\right )^{2}}{1+\left (d x +c \right )^{2}}\right )}{2}\right )+3 a \,b^{2} \left (\arctan \left (d x +c \right )^{2} \left (d x +c +i\right )+2 \arctan \left (d x +c \right ) \ln \left (1+\frac {\left (1+i \left (d x +c \right )\right )^{2}}{1+\left (d x +c \right )^{2}}\right )-2 i \arctan \left (d x +c \right )^{2}-i \operatorname {polylog}\left (2, -\frac {\left (1+i \left (d x +c \right )\right )^{2}}{1+\left (d x +c \right )^{2}}\right )\right )+3 a^{2} b \left (\left (d x +c \right ) \arctan \left (d x +c \right )-\frac {\ln \left (1+\left (d x +c \right )^{2}\right )}{2}\right )}{d}\) | \(279\) |
default | \(\frac {\left (d x +c \right ) a^{3}+b^{3} \left (\arctan \left (d x +c \right )^{3} \left (d x +c +i\right )-2 i \arctan \left (d x +c \right )^{3}+3 \arctan \left (d x +c \right )^{2} \ln \left (1+\frac {\left (1+i \left (d x +c \right )\right )^{2}}{1+\left (d x +c \right )^{2}}\right )-3 i \arctan \left (d x +c \right ) \operatorname {polylog}\left (2, -\frac {\left (1+i \left (d x +c \right )\right )^{2}}{1+\left (d x +c \right )^{2}}\right )+\frac {3 \operatorname {polylog}\left (3, -\frac {\left (1+i \left (d x +c \right )\right )^{2}}{1+\left (d x +c \right )^{2}}\right )}{2}\right )+3 a \,b^{2} \left (\arctan \left (d x +c \right )^{2} \left (d x +c +i\right )+2 \arctan \left (d x +c \right ) \ln \left (1+\frac {\left (1+i \left (d x +c \right )\right )^{2}}{1+\left (d x +c \right )^{2}}\right )-2 i \arctan \left (d x +c \right )^{2}-i \operatorname {polylog}\left (2, -\frac {\left (1+i \left (d x +c \right )\right )^{2}}{1+\left (d x +c \right )^{2}}\right )\right )+3 a^{2} b \left (\left (d x +c \right ) \arctan \left (d x +c \right )-\frac {\ln \left (1+\left (d x +c \right )^{2}\right )}{2}\right )}{d}\) | \(279\) |
parts | \(a^{3} x +\frac {b^{3} \left (\arctan \left (d x +c \right )^{3} \left (d x +c +i\right )-2 i \arctan \left (d x +c \right )^{3}+3 \arctan \left (d x +c \right )^{2} \ln \left (1+\frac {\left (1+i \left (d x +c \right )\right )^{2}}{1+\left (d x +c \right )^{2}}\right )-3 i \arctan \left (d x +c \right ) \operatorname {polylog}\left (2, -\frac {\left (1+i \left (d x +c \right )\right )^{2}}{1+\left (d x +c \right )^{2}}\right )+\frac {3 \operatorname {polylog}\left (3, -\frac {\left (1+i \left (d x +c \right )\right )^{2}}{1+\left (d x +c \right )^{2}}\right )}{2}\right )}{d}+\frac {3 a^{2} b \left (\left (d x +c \right ) \arctan \left (d x +c \right )-\frac {\ln \left (1+\left (d x +c \right )^{2}\right )}{2}\right )}{d}+\frac {3 a \,b^{2} \left (\arctan \left (d x +c \right )^{2} \left (d x +c +i\right )+2 \arctan \left (d x +c \right ) \ln \left (1+\frac {\left (1+i \left (d x +c \right )\right )^{2}}{1+\left (d x +c \right )^{2}}\right )-2 i \arctan \left (d x +c \right )^{2}-i \operatorname {polylog}\left (2, -\frac {\left (1+i \left (d x +c \right )\right )^{2}}{1+\left (d x +c \right )^{2}}\right )\right )}{d}\) | \(280\) |
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\[ \int (a+b \arctan (c+d x))^3 \, dx=\int { {\left (b \arctan \left (d x + c\right ) + a\right )}^{3} \,d x } \]
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\[ \int (a+b \arctan (c+d x))^3 \, dx=\int \left (a + b \operatorname {atan}{\left (c + d x \right )}\right )^{3}\, dx \]
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\[ \int (a+b \arctan (c+d x))^3 \, dx=\int { {\left (b \arctan \left (d x + c\right ) + a\right )}^{3} \,d x } \]
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\[ \int (a+b \arctan (c+d x))^3 \, dx=\int { {\left (b \arctan \left (d x + c\right ) + a\right )}^{3} \,d x } \]
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Timed out. \[ \int (a+b \arctan (c+d x))^3 \, dx=\int {\left (a+b\,\mathrm {atan}\left (c+d\,x\right )\right )}^3 \,d x \]
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